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Advanced ⛓ Discrete Math & Number Theory Topic 33 of 103

Permutations with Repetition

Arrange objects when some are identical.

Key idea

Arrange objects when some are identical.

In depth

If some items are identical, divide by the factorial of each repeat count: n!/(n₁!n₂!...). Dividing removes the arrangements that only swap identical items.

Worked example

Arrangements of MISSISSIPPI: 11!/(4!4!2!) = 34,650.

Formula

n!/(n₁!n₂!…)

Real-world uses

Common mistake

Forgetting to divide for each repeated letter.

How to learn this

  1. Read the key idea and say it in your own words.
  2. Work through the worked example, then try a similar problem.
  3. Use the interactive lesson’s visual and mini-quiz to check the pattern.

Frequently asked questions

What is Permutations with Repetition?

Arrange objects when some are identical. It is a topic at the advanced level in Discrete Math & Number Theory.

What is the formula for Permutations with Repetition?

The key formula is n!/(n₁!n₂!…).

Where is Permutations with Repetition used in real life?

Real-world examples: Counting distinct arrangements of letters in a word such as “BANANA” or the codes for a lock.

What should I learn before Permutations with Repetition?

Make sure you are comfortable with Factorials, the previous topic in Discrete Math & Number Theory.

What is a common mistake with Permutations with Repetition?

Forgetting to divide for each repeated letter.

How can I practise Permutations with Repetition?

Open the interactive lesson, play with the visual, then answer the three-question mini-quiz. Getting two right marks the topic complete.

What comes after Permutations with Repetition?

Move on to Circular Permutations next.

Related advanced topics in Discrete Math & Number Theory