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Expert △ Geometry Topic 76 of 100

Ceva’s Theorem

Condition for three cevians to be concurrent.

Key idea

Condition for three cevians to be concurrent.

In depth

Lines from the vertices of a triangle to points D, E, F on opposite sides are concurrent exactly when (AF/FB)(BD/DC)(CE/EA) = 1. It provides a quick test for concurrency, including medians and altitudes.

Worked example

If AF/FB = 2 and BD/DC = 3, then CE/EA must be 1/6 for concurrency.

Formula

(AF/FB)(BD/DC)(CE/EA) = 1

Real-world uses

Common mistake

Taking the ratios in inconsistent directions around the triangle.

How to learn this

  1. Read the key idea and say it in your own words.
  2. Work through the worked example, then try a similar problem.
  3. Use the interactive lesson’s visual and mini-quiz to check the pattern.

Frequently asked questions

What is Ceva’s Theorem?

Condition for three cevians to be concurrent. It is a topic at the expert level in Geometry.

What is the formula for Ceva’s Theorem?

The key formula is (AF/FB)(BD/DC)(CE/EA) = 1.

Where is Ceva’s Theorem used in real life?

Real-world examples: Checking that three cevians meet at one point; Advanced problem-solving in geometry contests.

What should I learn before Ceva’s Theorem?

Make sure you are comfortable with Nine-Point Circle, the previous topic in Geometry.

What is a common mistake with Ceva’s Theorem?

Taking the ratios in inconsistent directions around the triangle.

How can I practise Ceva’s Theorem?

Open the interactive lesson, play with the visual, then answer the three-question mini-quiz. Getting two right marks the topic complete.

What comes after Ceva’s Theorem?

Move on to Menelaus’ Theorem next.

Related expert topics in Geometry